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分形递归画图案图片DIY

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  • JAVA
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                                    递归,用最少的代码量完成最大的工作量,初步对递归开始上心是因为机试老师给了一道题,看到后开始着急忙慌就开始做,最后那个代码量,就不忍吐槽了,自己还觉得挺自豪的,写了那么多行代码,也打印出了正确图形,蠢话,结果老师一公布他的答案,和我几百行的代码相比老师只用了7行,完败。。。。。。。。。

于是觉得与其拿到题就开始做不如先找规律,本来思想就比代码重要,分形就是用递归画出美丽的图案,那些平时在我们眼中单调无趣的线条以及点,就能在不断递归中画出自然界之美。

我随意挑了两个比较有代表性的图案

画出的图如下所示:



 

 

 

 

以下是代码实现:

import java.awt.BorderLayout;

import java.awt.Color;
import java.awt.FlowLayout;
import java.awt.Graphics;
import java.util.Random;

import javax.swing.ImageIcon;
import javax.swing.JFrame;
import javax.swing.JLabel;

public class Main extends JFrame {
	 
    private Color color;
    double a,b,c,d;  
    
    double x1=0;  
    double y1=0;  
    double x2,y2;  
    public static void main(String[] args) {
             // TODO Auto-generated method stub
             Main a = new Main();
             a.draw();
 }
   
     public void draw(){//绘制界面,建立画布
         this.setSize(1000,800);//
         this.setLocationRelativeTo(null);
         this.setDefaultCloseOperation(3);
         this.setLayout(new FlowLayout());
         //设置可见
         this.setVisible(true);
        
         Graphics g = this.getGraphics();
         //调用·手镯图形
         this.magic(g);

     }
     //手镯图形,公式已经得知
     public void magic(Graphics g){
    	double a = 1.40,b = 1.56,c = 1.40, d = -6.56;   
         for(int i=0;i<12133;i++){  
             for(int t=0;t<80;t++){  
                 Color co = new Color(t++,t*2,t*3);  
                 g.setColor(co); }  
          
             double x2=d*Math.sin(a*x1)-Math.sin(b*y1);  
             double y2=c*Math.cos(a*x1)+Math.cos(b*y1);  
             int x22= (int) (x2*30)+300;  
             int y22=(int) (y2*30)+200;  
             System.out.println(x22+","+y22);  
             g.drawLine(x22,y22,x22,y22);  
             x1=x2;  
             y1=y2;}  
     }
     
     public void paint(Graphics g){
                      super.paint(g);
                      this.magic2(500,550,100, Math.PI/2,0,Math.PI/6,25,g);
                      //(Math.PI为180°)
     }
     
     public void magic2(double x0,double y0,double l,double a,double b,double c,double count,Graphics g){
    	ImageIcon cat=new ImageIcon("image//$R7U8UGI.gif");
 		ImageIcon dog=new ImageIcon("image//$RJT225K.gif");
 		ImageIcon panda=new ImageIcon("image//$RM069VP.gif");
 		
 
         double x2;
         double y2;
         double x3;
         double y3;
         double x4;
         double y4;
         double x5;
         double y5;
         Random r=new Random();
         //颜色随机变化
         color = new Color(r.nextInt(256),r.nextInt(256),r.nextInt(256));
         g.setColor(color);
         if(count<1)
         {
                  return;
         }//判断是否继续进行递归调用,注意:判断一定要放在递归调用之前,否则这段代码将永远不会被执行
   x2 = x0 - l*Math.cos(a);
   y2 = y0 - l*Math.sin(a);
   x3 = x2 - l*Math.cos(b);
   y3 = y2 - l*Math.sin(b);
   x4 = x0 - l*Math.cos(b);
   y4 = y0 - l*Math.sin(b);
   x5 = x2 - l*Math.cos(Math.PI/6)*Math.cos(c);
   y5 = y2 - l*Math.cos(Math.PI/6)*Math.sin(c);
//可画图形,计算五个点的位置,以右下点为(X0,Y0)
   //g.drawImage(cat.getImage(),(int)x0-300,(int)y0-300, null);
   //g.drawImage(panda.getImage(),(int)x2-300,(int)y2+300, null);
   //g.drawImage(dog.getImage(),(int)x3,(int)y3, null);
   //g.drawImage(cat.getImage(),(int)x4,(int)y4, null);
   //g.drawImage(panda.getImage(),(int)x5,(int)y5, null);
   g.drawLine((int)x0, (int)y0, (int)x2, (int)y2);
   g.drawLine((int)x2, (int)y2, (int)x3, (int)y3);
   g.drawLine((int)x3, (int)y3, (int)x4, (int)y4);
   g.drawLine((int)x4, (int)y4, (int)x0, (int)y0);
   g.drawLine((int)x2, (int)y2, (int)x5, (int)y5);
   g.drawLine((int)x5, (int)y5, (int)x3, (int)y3);
//递归调用
         magic2(x2,y2,l*Math.cos(Math.PI/6),a+Math.PI/6,b+Math.PI/6,c+Math.PI/6,count-1,g);
         magic2(x5,y5,l*Math.sin(Math.PI/6),a-Math.PI/3,b-Math.PI/3,c-Math.PI/3,count-1,g);

     }
     private Color getColor(int inc){
 		int red = color.getRed();
 		int green = color.getGreen();
 		int blue = color.getBlue();
 		red += inc;
 		green += inc;
 		blue += inc;
 		
 		if(red > 255)
 			red = 255;
 		if(green > 255)
 			green = 255;
 		if(blue > 255)
 			blue = 255;
 		return new Color(red,green,blue);
 	}



        
     }

 

 

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